Hello, I have xml data that I need to group and sort. I have tried
grouping it using the Muenchian Method. Probably not solved the best
way, but it works. But I can't get the sorting right.

Here's my XML:

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="channel.xslt"?>
<SearchResults>
	<SearchHit>
		<article>
			<field name="KANAL">
				<category path="//TV//Channels//Channel1" id="1"/>
			</field>
			<field name="TITTEL">Program 1</field>
			<field name="SCHEDULE">
			<schedule startTime="2400"/></field>
		</article>
		<article>
			<field name="KANAL">
				<category path="//TV//Channels//Channel2" id="2"/>
			</field>
			<field name="TITTEL">Program 2</field>
			<field name="SCHEDULE">
			<schedule startTime="0900"/></field>
		</article>
		<article>
			<field name="KANAL">
				<category path="//TV//Channels//Channel2" id="2"/>
			</field>
			<field name="TITTEL">Program 3</field>
			<field name="SCHEDULE">
			<schedule startTime="1100"/></field>
		</article>
		<article>
			<field name="KANAL">
				<category path="//TV//Channels//Channel2" id="2"/>
			</field>
			<field name="TITTEL">Program 4</field>
			<field name="SCHEDULE">
			<schedule startTime="1000"/></field>
		</article>
		<article>
			<field name="KANAL">
				<category path="//TV//Channels//Channel1" id="1"/>
			</field>
			<field name="TITTEL">Program 5</field>
			<field name="SCHEDULE">
			<schedule startTime="2100"></schedule></field>
		</article>
	</SearchHit>
</SearchResults>

Here's my XSLT:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="html" version="1.0" encoding="utf-16"
indent="yes"/>
	<xsl:key name="kChannel" match="article/field[@name='KANAL']/category"
use="@path" />
	<xsl:output method="html"/>
	<xsl:template match="SearchResults/SearchHit">
	<xsl:for-each
select="article/field[@name='KANAL']/category[generate-id()=generate-id(key('kChannel',
@path))]">
		<xsl:variable name="theArticle"
select="current()/parent::node()/parent::node()" />
		<xsl:variable name="ChannelName" select="@path" />
		<xsl:value-of select="$ChannelName" /><br/>
		<xsl:apply-templates
select="/SearchResults/SearchHit/article/field/category[@path =
current()/@path]" />
	</xsl:for-each>
	</xsl:template>

	<xsl:template match="category">
		<xsl:variable name="theArticle"
select="current()/parent::node()/parent::node()" />
		<xsl:value-of select="$theArticle/field[@name='TITTEL']"/> -
		<xsl:value-of
select="$theArticle/field[@name='SCHEDULE']/schedule/@startTime"/><br/>
                </xsl:template>
</xsl:stylesheet>

Here's my current output:

//TV//Channels//Channel1
Program 1- 2400
Program 5- 2100
//TV//Channels//Channel2
Program 2- 0900
Program 3- 1100
Program 4- 1000

I would like to sort the channels by its ID and the programs by its
startTime. Does anybody have an idea?

Any help would be appreciated!

Regards, 
A Hansen, XSLT newbie