Joe Kesselman wrote:
> johkar wrote:
> > One more question.  If data:data is on the main page, how can you
> > access it in an included xsl?
>
> I'm not sure what you mean by "main page" in this context. The main
> stylesheet? If you know the URI for that stylesheet, you can ask the
> document function to retrieve from that specific URI. If you don't know
> the URI, you may have to pass it down as a parameter ... or just pass a
> reference to that data:data element down as a parameter.

I have only been able to get one scenario to work, if I have the
data:data namespace and the document function on the same stylesheet.
If I want to output various nodes from the data:data XML from and
included stylesheet, I cannot get it to work. I have tried passing
references and other things suggested, but my syntax is apparently
incorrect.  We use Xalan if that makes a difference.  Below is an
example.

Thanks, John

Main template
<?xml version='1.0'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:data="http://example.com/2006/some-data">
<xsl:include href="common/leftcol.xsl" />

<data:data>
  <links xmlns="">
    <link name="selected">Link 1</link>
    <link>Link 2</link>
  </links>
</data:data>

   <xsl:template match="/">
        <xsl:call-template name="leftcol" />
   </xsl:template>
</xsl:stylesheet>

Left Column Template

<?xml version='1.0'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:data="http://example.com/2006/some-data">
   <xsl:template name="leftcol">
   <xsl:value-of
select="document(common/mainPage.xsl)/data:data/links/link[@name='selected']"
/>
   </xsl:template>
</xsl:stylesheet>