> How do I say: "for all nodes that are NOT  H, X and Z, do this:" ?

In XSLT one doesn't need to specifically write this.

you will have two templates:

   <xsl:template match="*">
      <!-- Whatever general transformation necessary here -->

   </xsl:template>

   <xsl:template match="H | X | Z">
     <!-- A more specialized transformation here -->

   </xsl:template>

The second template overrides the first for elements of type H, X, Z.

Just try it :o)


Cheers,
Dimitre Novatchev

<Piper707@h...> wrote in message 
news:1133433095.424099.72260@g......
> Hi,
>
> I need to know how I can check to see if a particular node is NOT equal
> to a SET of values.
>
> i.e. a valid form of : <xsl:template match!="H" && match!="Y"&&
> match!="Z">
>
> I have an XML document of the foll format:
>
> <ROOT>
> <A>1</A>
> <B>2</B>
> <C>3</C>
> ....
> <H>4</H>
> ...
> </ROOT>
>
> I need to transform this into another format. Only the nodes <H>, <X>,
> <Z> need special handling, which i refer to, via a corresponding
> template calls.
>
> All the other nodes, need to be transformed like this:
>
> <A>1</A>  becomes <A><Value>1</Value></A>
>
> My xsl looks something like this:
>
> <xsl:template match="/">
> <NEWFORM>
>   <xsl:apply-templates/>
> </NEWFORM>
> </xsl:template>
>
> /****template calls for H, X, Z**********/
>
> <xsl:template match="H">
> //special handling for <H>
> </xsl:template>
>
> How do I say: "for all nodes that are NOT  H, X and Z, do this:" ?
>
> something like:
>
> for each child of root
> not equal to X, H, Z
>   do the following:
>
> Thanks for any help
> Rohit.
>