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XSL: NOT equal checking for node?

From: Piper707@-------.---
To: NULL
Date: 12/1/2005 2:32:00 AM
Hi,

I need to know how I can check to see if a particular node is NOT equal
to a SET of values.

i.e. a valid form of : <xsl:template match!="H" && match!="Y"&&
match!="Z">

I have an XML document of the foll format:

<ROOT>
<A>1</A>
<B>2</B>
<C>3</C>
....
<H>4</H>
...
</ROOT>

I need to transform this into another format. Only the nodes <H>, <X>,
<Z> need special handling, which i refer to, via a corresponding
template calls.

All the other nodes, need to be transformed like this:

<A>1</A>  becomes <A><Value>1</Value></A>

My xsl looks something like this:

<xsl:template match="/">
<NEWFORM>
   <xsl:apply-templates/>
</NEWFORM>
</xsl:template>

/****template calls for H, X, Z**********/

<xsl:template match="H">
//special handling for <H>
</xsl:template>

How do I say: "for all nodes that are NOT  H, X and Z, do this:" ?

something like:

for each child of root
 not equal to X, H, Z
   do the following:

Thanks for any help
Rohit.



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