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Re: xslt merging question

From: Martin Honnen <mahotrash@-----.-->
To: NULL
Date: 11/1/2005 6:15:00 PM

rottyguy70@y... wrote:


> 1) static xml
> <items>
>   <item id="1" type="clothes"/>
>   <item id="2" type="cars"/>
>   <item id="3" type="tvs"/>
> </items>

> 2) i need to derive a unique set from the following:
> <new-items>
>   <new-item type="house"/>
>   <new-item type="boats"/>
> </new-items>
> 
> <new-items>
>   <new-item type="windows"/>
>   <new-item type="boats"/>
> </new-items>
> 
> ** i can use muenchian to get uniques

If those are two different documents then I think grouping with key is 
difficult as I think a key applies always to nodes in one particular 
document but not across documents. You might need an extra step that 
first combines those two documents.

> 2b) i need to combine (1) with (2) to get:
> <items>
>   <item id="1" type="clothes"/>
>   <item id="2" type="cars"/>
>   <item id="3" type="tvs"/>
>   <item id="4" type="house"/>
>   <item id="5" type="boats"/>
>   <item id="6" type="windows"/>
> </items>

Well you can certainly do

<xsl:variable name="itemCount" select="count(items/item)" />

and

<xsl:template match="items">
   <xsl:copy>
     <xsl:apply-templates select="@*" />
     <xsl:apply-templates select="item" />
     <xsl:variable name="new-items" 
select="document('test2005110102.xml', /)/new-items/new-item" />
     <xsl:apply-templates select="$new-items[not(@type = 
preceding-sibling::new-item/@type)]" />
   </xsl:copy>
</xsl:template>

and

<xsl:template match="new-item">
   <item id="{$itemCount + position()}" type="{@type}" />
</xsl:template>



-- 

	Martin Honnen
	http://JavaScript.FAQTs.com/


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