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Re: Xml Schema substitution groups / key keyref

From: "John Carron" <John Carron@------.--->
To: NULL
Date: 9/2/2005 7:23:00 PM
Hi Priscilla ,

Many thanks for the reply.  It worked a treat.

Thanks again

Darren

"Priscilla Walmsley" <nospam@d...> wrote in message 
news:TaYRe.3$1u4.1219@n......
> Hi,
>
> If you want the identifiers to be unique across all reports and targets,
> you can add this to your declaration of the Request element:
>
> <xs:key name="uniqueIDs">
>  <xs:selector xpath="*"/>
>  <xs:field xpath="@identifier"/>
> </xs:key>
>
> If you only want the identifiers to be unique among targets (and not
> reports) and you know all the target element names in advance, you could
> use:
>
> <xs:key name="uniqueIDs">
>  <xs:selector xpath="demo:DummyTarget|demo:DummyTarget2"/>
>  <xs:field xpath="@identifier"/>
> </xs:key>
>
> But, if you only want the identifiers to be unique among targets, and
> you don't want to hard code the names in there, I think you'd have to
> use a different attribute name for target IDs vs. report IDs.
>
> To enforce the reference, you can use:
>
> <xs:keyref name="validRefs" refer="uniqueIDs">
>  <xs:selector xpath=".//demo:TargetReference"/>
>  <xs:field xpath="@identifier"/>
> </xs:keyref>
>
> Note that I use a "demo" prefix - You would have to map your target
> namespace to a prefix in your schema in order for this to work, because
> XPath expressions do not take into account default namespace
> declarations.
>
> Hope that helps,
> Priscilla
>
> ----------------------------------
> Priscilla Walmsley
> Author, Definitive XML Schema
> http://www.datypic.com
> ----------------------------------
>
> *** Sent via Developersdex http://www.developersdex.com *** 




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