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XSLT: please help with XPath-expression

From: Gerald Aichholzer <gary@----.------.-->
To: NULL
Date: 6/1/2005 1:55:00 PM
Hello NG,

I have a XML file looking like this:

   <symbol>
     <objectgroup objid="abc">
       <plugin pid="plugin1" href="..."/>
       <plugin pid="plugin3" href="..."/>
     </objectgroup>
     <objectgroup objid="def">
       <!-- ... -->
     </objectgroup>
     <!-- even more objectgroup elements -->
     <plugins>
       <plugin pid="plugin1"><desc>...</desc></plugin>
       <plugin pid="plugin2"><desc>...</desc></plugin>
       <plugin pid="plugin3"><desc>...</desc></plugin>
     </plugins>
   </symbol>

For each objectgroup/plugin element I'd like to access the
corresponding plugins/plugin element using the following
template:

   <xsl:template match="objectgroup">
     <!-- do something -->
     <xsl:for-each select="./plugin">
       <xsl:value-of select="/symbol/plugins/plugin[???]/desc"/>
                                                    ^^^
     </xsl:for-each>                                 |
     <!-- do something -->                           |
   </xsl:template>                                   |
                                                     |
+---------------------------------------------------+
v

How can I select /symbol/plugins/plugin haven the same pid
as the current pid in the xsl:for-each loop?

thanks in advance,
Gerald


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