inquirydog@h... (inquirydog) writes:

> Hi-
> 
>         Thanks for the reply.  I looked into it a bit and found that
> in XSLT 2 you can define xpath functions using xslt elements.  This
> certainly makes a solution like this more reasonable.  It does still
> leave certain problems like counting repeat nodes in a list....  For
> instance, if you wanted to eliminate doubles in a list like this
> 
> <list>
>         <element name="1" />
>         <element name="2" />
>         <element name="1" />
>         <element name="1" />
>         <element name="1" />
>         <element name="2" />
> </list>
> 
> converting to
> 
> <list>
> 
>         <element name"1" count="4" />
>         <element name="2" count="2" />
> 
> </list>
> 
> you need to group by element type and then count the number of
> elements.  Except for very constrained cases this seems to me to be
> impossible to do in xslt (yes I know about the muenchian method- it
> only works in a constrained case).  To do this grouping you need to
> first be able to check for node equality (which I think you can do in
> xslt 2) and then do the grouping based on the equality (which is
> better supported in xslt 2 but still can't do what I describe in this
> email).
> 

What do you mean by

> but still can't do what I describe in this email.

?

Your grouping example seems quite simple to do in either XSLT1 or XSLT2,
it might loook a bit simpler in 2 using the explict xsl:for-each-group
mechanism, but it doesn't take much code in either case.

For example in 1.0 it would be:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:key name="x" match="element" use="@name"/>

<xsl:template match="list">
 <list>
  <xsl:for-each select="element[generate-id()=generate-id(key('x',@name))]">
   <element name="{@name}" count="{count(key('x',@name))}"/>
  </xsl:for-each>
 </list>
</xsl:template>

</xsl:stylesheet>



David